Apple ACPT Certification Exam 9L0-402

When more than one operator appears in an expression the order of evaluation depends on the rules of 9L0-509 precedence. A complete explanation of precedence can get complicated, but just to get you started:

Multiplication and division happen before addition and subtraction. So 2*3-1 yields 5, not 4, and 2/3-1 yields -1, not 1 (remember that in integer division 2/3 is 0). If the operators have the same precedence they are evaluated from left to right. So in the expression minute*100/60, the multiplication happens first, yielding 5900/60, which in turn yields 98. If the operations had gone from right to left, the result would be 59*1 which is 59, which is wrong. Any time you want to override the rules of precedence (or you are not sure what they are) you can use parentheses. Expressions in parentheses are evaluated first, so 2 * (3-1) is 4. You can also use parentheses to make an expression easier to read, as in (minute * 100) / 60, even though it doesn't Testking 9L0-402 change the result.
The line illustrates what is called chaining of insertion operators to print multiple expressions. How this works is as follows:

1. The 9L0-509 leftmost insertion operator takes as its operands, std::cout and the string "The sum of ", it prints the latter using the former, and returns a reference to the former.
2. Now std::cout << a is evaluated. This prints the value contained in the location a, i.e. 123 and again returns std::cout.
3. This process continues. Thus, successively the expressions std::cout << " and ", std::cout << Pass4sure 9L0-402 b, std::cout << " is ", std::cout << " sum ", std::cout << "\n" are evaluated and the whole series of chained values is printed.